What does KaKb equal to in the context of water at equilibrium?

Prepare for the ACS Inorganic Chemistry Exam. Study using flashcards and multiple-choice questions, each with hints and explanations.

In the context of water at equilibrium, KaKb equals Kw, which refers to the dissociation constants of weak acids (Ka) and weak bases (Kb) in water. This relationship emerges from the fact that when an acid donates a proton (H⁺) to water, it forms hydronium ions (H₃O⁺), and the equilibrium can be established in such a way that the product of the concentrations of H₃O⁺ and OH⁻ ions in pure water, denoted as Kw, is always maintained at a constant value of 1.0 x 10⁻¹⁴ at 25°C.

Thus, for any conjugate acid-base pair, the product of their dissociation constants provides a way to understand how they interact in solution. Specifically, if you have an acid dissociating and a base also associating in that same solution, their respective constants multiplied together will yield Kw. This establishes a fundamental link between acid-base chemistry and the broader aspects of water chemistry, essential for various applications in both inorganic and organic chemistry.

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